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Is that the right idea or not?Ok, 0 is not even in f.

So then let f:(0,1)-->(0,1] and let g:(0,1)-->[0,1]

Let f(x)=g(x) for all x in (0,1)

Is this part correct? I know there needs to be some number to equal 0 right?

Let g(x)=f(x)=?

I just am unsure of what x value to plug into g(x)=0