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## Main Question or Discussion Point

Hi all,

I have a suspicion this may be obvious but have lookd and can't seem to obtain the correct answer,

Can somone please explain the steps required to prove

ABC^TA^-1=CB

where C^T is the transpose of C and A^-1 the inverse of A. Matrices B and A are covariance matrices and thus may be considered symmetric if that helps

Thanks in advance for some direction

I have a suspicion this may be obvious but have lookd and can't seem to obtain the correct answer,

Can somone please explain the steps required to prove

ABC^TA^-1=CB

where C^T is the transpose of C and A^-1 the inverse of A. Matrices B and A are covariance matrices and thus may be considered symmetric if that helps

Thanks in advance for some direction