- #1
asset101
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let an = [tex]\frac{(2n+1)}{(3n+7)}[/tex]. Prove direct from definition that an[tex]\rightarrow2/3[/tex].
Any help would be appreciated.
Cheers
Any help would be appreciated.
Cheers
That's the simplest way of finding the limit but it doesn't "prove from the definition".Here's an idea... as long as n isn't zero, the following two things are the same:
(2n+1)/(3n+7) = [(2n)(1+1/2n)]/[(3n)(1+7/3n)]
What happens as the n's get bigger and bigger to the terms 1/2n and 7/3n?