Prove F(-x) = -F(x) for all x

  • Thread starter Noorac
  • Start date
In summary: If you integrate and take the limit as x approaches -∞, you get the symmetric function. So, if you integrate and take the limit as x approaches -∞, you get \displaystyle \int_{-∞}^{x} f(t) dt = \displaystyle \int_{0}^{x} f(t) dt
  • #1
Noorac
13
0
f(x)
=[itex]\frac{arctan x}{x}[/itex] for x different from 0
= 1 for x equal to 0

F(x) is a definite integral from 0 to x, but I couldn't find the code for it, so just assume it is from 0 to x in the equation below.

F(X) = [itex]\int f(t) dt[/itex]

Now, the task is to prove that F(-x) = -F(x).

This means we need to prove:

[itex]\int f(t) dt[/itex] : definite from 0 to -x

=

-[itex]\int f(t) dt[/itex] : definite from 0 to x
_____________________________________

We have tried some basic manipulation of integrals, but came nowhere.

If anyone can give a hint of how to prove this, or tell us if we have understood the problem wrong, we would be most grateful.

Thanks.
 
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  • #2
Noorac said:
f(x)
= [itex]\displaystyle \frac{\arctan(x)}{x}[/itex] for x different from 0
= 1 for x equal to 0

F(x) is a definite integral from 0 to x, but I couldn't find the code for it, so just assume it is from 0 to x in the equation below.

F(x) = [itex]\displaystyle \int_{0}^{x} f(t) dt[/itex]

Now, the task is to prove that F(-x) = -F(x).

This means we need to prove:

[itex]\displaystyle \int_{0}^{-x} f(t) dt[/itex] : definite from 0 to -x

=

[itex]\displaystyle -\int_{0}^{x} f(t) dt[/itex] : definite from 0 to x
_____________________________________

We have tried some basic manipulation of integrals, but came nowhere.

If anyone can give a hint of how to prove this, or tell us if we have understood the problem wrong, we would be most grateful.

Thanks.

The way to include limits of integration in LaTeX code is to use the subscript & superscript with the integral symbol: \int_{0}^{x} in your case. Using the \displaystyle code will make Large integral symbols and fractions when using [​itex​] & [​/itex​] tags.

The code:
Code:
[itex]\displaystyle -\int_{0}^{x} f(t) dt[/itex]
gives you [itex]\displaystyle -\int_{0}^{x} f(t) dt[/itex] .
 
  • #3
A quick way to look at this: what is the symmetry (about the y-axis) of the function [itex]\frac{arctan x}{x}[/itex]? (It is the ratio of two functions -- what are their symmetries and so what is the symmetry of the ratio?). Then, what does it mean to integrate [itex]\int_{0}^{x} f(t) dt[/itex] and [itex]\int_{0}^{-x} f(t) dt[/itex] for a function f(x) with such a symmetry?
 

1. How do you prove F(-x) = -F(x) for all x?

To prove this statement, we can use the definition of an even function. An even function is one where f(-x) = f(x) for all x. Since we know that F(x) is an even function, we can substitute -x for x in the definition and get F(-x) = F(x). This shows that F(-x) and -F(x) are equal, proving the statement.

2. What is the significance of proving F(-x) = -F(x) for all x?

This statement shows that F(x) is an even function, meaning that it is symmetrical about the y-axis. This can be useful in many mathematical applications, such as graphing and solving equations.

3. Can this statement be proven for all types of functions?

Yes, this statement can be proven for all types of functions as long as they are even. However, if the function is not even, then the statement may not hold true.

4. Is there a visual way to understand this statement?

Yes, you can visualize this statement by graphing an even function. The graph will be symmetrical about the y-axis, meaning that the points on one side of the y-axis will have the same y-values as the points on the other side. This demonstrates that F(-x) = F(x).

5. Can you provide an example of an even function to illustrate this statement?

One example of an even function is f(x) = x^2. If we substitute -x for x, we get f(-x) = (-x)^2 = x^2 = f(x). This shows that the function is symmetrical about the y-axis and F(-x) = F(x) for all x.

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