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judahs_lion
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Homework Statement
Given S = (1+x2, x +x3
And augment S to form a Basis S' of P3
The Attempt at a Solution
0 + 0x + 0x2 + 0x3 = a(1+x2)+b(x +x3)
= a + ax2 + bx + bx3
I'm pretty sure you mean, S = {1 + x2, x + x3}judahs_lion said:Homework Statement
Given S = (1+x2, x +x3
It would be helpful for you to state the complete problem. My guess is that it is two parts:judahs_lion said:And augment S to form a Basis S' of P3
The Attempt at a Solution
0 + 0x + 0x2 + 0x3 = a(1+x2)+b(x +x3)
= a + ax2 + bx + bx3
Prob. 15 is almost identical to prob. 13. The polynomials in P3 are essentially the same as vectors in R4. For example, 1 + 2x2 <---> <1, 0, 2, 0>.judahs_lion said:I scanned it in. Its problem # 15
This isn't the definition, and besides, a definition of a term ought not use the same term in the definition. Look in your book and see how it defines linear independence.judahs_lion said:Linear independence mean the members of a set of vectors are independent of each other.
This is a necessary condition for linear independence, but it is not sufficient. For example, consider the set {<1, 0, 0>, <0, 1, 0>, <1, 1, 0>}. None of these vectors is a multiple of any other vector in the set, yet these vectors are not linearly independent.judahs_lion said:None is a multiple of the other.
Mark44 said:This isn't the definition, and besides, a definition of a term ought not use the same term in the definition. Look in your book and see how it defines linear independence.
This is a necessary condition for linear independence, but it is not sufficient. For example, consider the set {<1, 0, 0>, <0, 1, 0>, <1, 1, 0>}. None of these vectors is a multiple of any other vector in the set, yet these vectors are not linearly independent.
Mark44 said:Yes.
The P3 basis S is a set of three vectors that form a basis for a three-dimensional vector space. It is commonly used in linear algebra and is denoted as {s1, s2, s3}.
Proving the independence of the P3 basis S is crucial in determining if the three vectors in the set are linearly independent. This means that none of the vectors can be written as a linear combination of the other two, which is important in many mathematical and scientific applications.
To prove the independence of P3 basis S, you must show that the only solution to the equation c1s1 + c2s2 + c3s3 = 0 is when c1 = c2 = c3 = 0. This can be done through various methods, such as using Gaussian elimination or the determinant test.
If the P3 basis S is not independent, it means that at least one of the vectors can be written as a linear combination of the other two. This can lead to errors and inaccuracies in calculations and can also affect the overall results and conclusions in scientific studies.
Yes, there are many real-world applications of proving the independence of P3 basis S. For example, it is used in computer graphics to determine if a set of three vectors can form a three-dimensional object. It is also important in physics, engineering, and economics for solving problems involving three-dimensional vector spaces.