Show that: 2ab <= a^2 + b^2(adsbygoogle = window.adsbygoogle || []).push({});

It follows that 0 <= (a - b)^2 is going to be always positive, then inequelity holds. But I think I need to prove that 2 times a times b has to be less than equal to the sum of the squares of a and b.

Any suggestions?

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# Prove inequality 2ab <= a^2 + b^2 from 0 <= (a - b)^2

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