- #1

Mentallic

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## Homework Statement

I need to prove that [tex]\sqrt{3}[/tex] is irrational.

## The Attempt at a Solution

The prior problem was to show [tex]\sqrt{2}[/tex] is irrational and the solution had to do with a contradiction that each number must be even or something (frankly, I didn't understand it too well). But I don't see how I can apply the same idea to this one, since evenness is not applicable here.

All i can really do so far is assume [tex]\sqrt{3}=\frac{p}{q}[/tex] where p and q are integers.

Now, by squaring, [tex]3q^2=p^2[/tex].

I am completely lost here though...

Some help please?