- #1
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Homework Statement
I need to prove that [tex]\sqrt{3}[/tex] is irrational.
The Attempt at a Solution
The prior problem was to show [tex]\sqrt{2}[/tex] is irrational and the solution had to do with a contradiction that each number must be even or something (frankly, I didn't understand it too well). But I don't see how I can apply the same idea to this one, since evenness is not applicable here.
All i can really do so far is assume [tex]\sqrt{3}=\frac{p}{q}[/tex] where p and q are integers.
Now, by squaring, [tex]3q^2=p^2[/tex].
I am completely lost here though...
Some help please?