(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Prove

lim x/(x+1) = 1/2

x->1

2. Relevant equations

3. The attempt at a solution

|x/(x+1) - 1/2|=|x-1|/(2|x+1|)

Assume x>0 (can I say this??), then |x-1|/(2|x+1|)<|x-1|/2

Take delta=min{1,epsilon/2}.

Then if 0<|x-1|<delta, then |x/(x+1) - 1/2|<epsilon

In the middle of my proof, I assumed that x>0, is this OK?

Does my choice of delta (delta=min{1,epsilon/2}) work?

Could someone kindly confirm this? (or point out any mistakes)

I haven't done those for awhile, so I'm not sure if I'm doing it correctly.

Thanks!

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# Homework Help: Prove lim x/(x+1) = 1/2

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