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I am trying to prove that the skid to stop formula works with vehicles of different weight, with the use of kinetic energy. I think I have proven this, but if someone would like to check this over to make sure I am correct I would appreciate it.

13000 kg vehicle leaves skid marks 21 meters long, the drag factor is .7

13000 * 21 * .7 = 191100 joules

V = sqr ((2gKE)/w)

V = sqr ((2* 9.81*191100))/13000)

V = sqr (3749382/13000)

V = sqr 288.414

V = 16.98 m/s

S = 16.98 / .2777

S = 61.14 km/h

2000 kg vehicle leaves skid marks 21 meters long, the drag factor is .7

2000 * 21 * .7 = 29400 joules

V = sqr ((2gKE)/w)

V = sqr ((2* 9.81*29400))/2000)

V = sqr (576828/2000)

V = sqr 288.414

V = 16.98 m/s

S = 16.98 / .2777

S = 61.14 km/h

This is the skid to stop formula.

S = sqr (254 µ d ))

S = sqr (254 * .7 * 21))

S = sqr 3733.8

S = 61.10 km/h

13000 kg vehicle leaves skid marks 21 meters long, the drag factor is .7

13000 * 21 * .7 = 191100 joules

V = sqr ((2gKE)/w)

V = sqr ((2* 9.81*191100))/13000)

V = sqr (3749382/13000)

V = sqr 288.414

V = 16.98 m/s

S = 16.98 / .2777

S = 61.14 km/h

2000 kg vehicle leaves skid marks 21 meters long, the drag factor is .7

2000 * 21 * .7 = 29400 joules

V = sqr ((2gKE)/w)

V = sqr ((2* 9.81*29400))/2000)

V = sqr (576828/2000)

V = sqr 288.414

V = 16.98 m/s

S = 16.98 / .2777

S = 61.14 km/h

This is the skid to stop formula.

S = sqr (254 µ d ))

S = sqr (254 * .7 * 21))

S = sqr 3733.8

S = 61.10 km/h

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