Prove: (tan y + Cot y) sin y cos y = 1

  • Thread starter Jasonp914
  • Start date
  • #1
7
0
Hi, I need to prove:

(tan y + Cot y) sin y cos y = 1

I've gotten this far and got stuck:

(tany + cos y) sin y cos y changed Cot to reciprical
--------sin y

(sin y tany + cosy) sin y cos y common demonator
--------siny

(sin y tany + cos y) cosy multipyied by sin y

then i could distribute

cos y sin y tan y + cos(sqared) y but how would that equal 1?

thanks for your time.
 
Last edited:

Answers and Replies

  • #2
551
1
It should help if you plug in

[tex]\tan x = \frac{\sin x}{\cos x}[/itex]
 
Last edited:
  • #3
210
0
just a suggestion of my own, but try expressing those ratios literally in terms of fractions (ie: sin theta = o/h)...simplify the equation now and see if you notice anything familiar.
 
  • #4
7
0
o got it thank you!
 

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