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Prove the hyperbolic function corresponding to the given trigonometric function
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[QUOTE="robphy, post: 6824888, member: 9587"] The first equality is true. The second is not. Maybe your first line should read ##3-4\cosh 2u+\cosh 4u ## ##=3-4(1+2\sinh^2 u)+ \cosh ( 2u+2u)## ##=...## The problem is really about finding the hyperbolic-analogue of a trigonometric identity. So, start with a hyperbolic analogue on one side (probably the simpler side) and find an identity for it involving hyperbolic functions. If you do it by substitution, you must use complex numbers (as I hinted in my early post #6). [/QUOTE]
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Prove the hyperbolic function corresponding to the given trigonometric function
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