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Prove using Boolean algebra that two expressions are equivalent
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[QUOTE="rugerts, post: 6246704, member: 645847"] Does this simplify to: A'D * [ C + 1 ] = A'D? Since C+1 = 1. If so, I have the expression now and it looks like I've shown I can go from minimal P.O.S. to minimal S.O.P. Is it also true I can go the other way (i.e. minimal SOP to minimal POS)? I originally tried doing this but it seemed to be more difficult. Also, you said in the original post that you're not sure if it's possible to convert between the canonical forms... why would that be so? For me, it seems like that should be possible. Thanks. [/QUOTE]
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Prove using Boolean algebra that two expressions are equivalent
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