# Prove X-x = 0

i see

jgens
Gold Member

x=nPi that has a variable though ... x= tsro1 doesnt
If the presence/absence of a variable is throwing you off, that's an easy matter to fix. If $x$ is a number such that $x^2 = 1$ then $x = n(1)$ where $n=1$ or $n=-1$. This is exactly what everyone else has been saying!

Just use 'root'. It has the same number of letters and has the advantage of not having to be explained.
haha true

If the presence/absence of a variable is throwing you off, that's an easy matter to fix. If $x$ is a number such that $x^2 = 1$ then $x = n(1)$ where $n=1$ or $n=-1$. This is exactly what everyone else has been saying!
ok!!

jgens
Gold Member

Just use 'root'.
Or "sqrt" . . .

ahh but root uses a double o and all the letters are on the same line ... its just more efficient haha

jgens
Gold Member

It may be more efficient but it's also ambiguous. We could use "root" to represent any nth root whereas "sqrt" specifically denotes the squareroot.

also true

so (sqrt 1 - sqrt 1) is different to
x=sqrt 1
x-x

DaveC426913
Gold Member

so (sqrt 1 - sqrt 1) is different to
x=sqrt 1
x-x
(sqrt 1 - sqrt 1) has 4 possible solutions.

jgens
Gold Member

so (sqrt 1 - sqrt 1) is different to
x=sqrt 1
x-x
No! Hopefully without confusing you too much, if we let $x = \sqrt{1}$ then $x=1$ because the $\sqrt$ operation retrieves the principal (positive) square root. However, if $x$ is a number such that $x^2 = 1$ then $x=1$ or $x=-1$. Now, using this second definition of $x$, once we choose a value for $x$ we need to stick with it. We can't have $x = 1$ and $x = -1$ at the same time because this would violate the law of non-contradiction and you're already assuming that $1 = -1$.

Stop feeding the troll (OP)!