- #26

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i see

- Thread starter chalky00
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- #26

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i see

- #27

jgens

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If the presence/absence of a variable is throwing you off, that's an easy matter to fix. If [itex]x[/itex] is a number such that [itex]x^2 = 1[/itex] then [itex]x = n(1)[/itex] where [itex]n=1[/itex] or [itex]n=-1[/itex]. This is exactly what everyone else has been saying!x=nPi that has a variable though ... x= tsro1 doesnt

- #28

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haha trueJust use 'root'. It has the same number of letters and has the advantage of not having to be explained.

- #29

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ok!!If the presence/absence of a variable is throwing you off, that's an easy matter to fix. If [itex]x[/itex] is a number such that [itex]x^2 = 1[/itex] then [itex]x = n(1)[/itex] where [itex]n=1[/itex] or [itex]n=-1[/itex]. This is exactly what everyone else has been saying!

- #30

jgens

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- #31

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ahh but root uses a double o and all the letters are on the same line ... its just more efficient haha

- #32

jgens

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It may be more efficient but it's also ambiguous. We could use "root" to represent any nth root whereas "sqrt" specifically denotes the squareroot.

- #33

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also true

- #34

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so (sqrt 1 - sqrt 1) is different to

x=sqrt 1

x-x

- #35

DaveC426913

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(sqrt 1 - sqrt 1) has 4 possible solutions.so (sqrt 1 - sqrt 1) is different to

x=sqrt 1

x-x

- #36

jgens

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No! Hopefully without confusing you too much, if we let [itex]x = \sqrt{1}[/itex] then [itex]x=1[/itex] because the [itex]\sqrt[/itex] operation retrieves the principal (positive) square root. However, if [itex]x[/itex] is a number such that [itex]x^2 = 1[/itex] then [itex]x=1[/itex]so (sqrt 1 - sqrt 1) is different to

x=sqrt 1

x-x

- #37

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Stop feeding the troll (OP)!

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