- #1

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How to prove this?? I am not finding anyway to it.

You're my last hope!

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- Thread starter M. next
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- #1

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How to prove this?? I am not finding anyway to it.

You're my last hope!

- #2

Simon Bridge

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http://en.wikipedia.org/wiki/4_vector

http://teachers.web.cern.ch/teachers/archiv/hst2002/bubblech/mbitu/velocity_4vector.htm

- #3

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- #4

Simon Bridge

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If you do not know how a 4-vector transforms, then learn and revisit the problem of a proof later.

- #5

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http://en.wikipedia.org/wiki/4_vector#Derivatives_and_differentials

Then note that [itex]\mathrm{d} \tau[/itex] is a scalar. Then you can easily prove yourself that [itex]u^{\mu}[/itex] is a four-vector!

- #6

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- #7

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sorry I meant if I took Ui and divided that by ..

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