Prove that f(x) = 1/(x^2) is not continuous at x = 0 using the epsilon and delta definition of a limit
definition of discontinuity
There exist epsilon > 0 such that for all delta > 0 there is an x such that |x-0| < delta but |1/(x^2)| >= Epsilon
The Attempt at a Solution
I don't know how to go from here. Like how do i prove it? I don't understand!