1. The problem statement, all variables and given/known data Let G be a group and define λg:G→G to be λg(x)=g.x , x[itex]\in[/itex]G. Show that λg is onto and one-to-one. 3. The attempt at a solution Suppose g.x=g.x' g-1.g.x=g-1.g.x' which means x=x'. How should I show that the function is onto?