1. The problem statement, all variables and given/known data Here's an excerpt from a book called "Algebra made easy". Needless to say I have taken algebra before and done well in it this is only the first chapter in the book, but I feel very lost at understanding this, its confusing. Here's another example of it. I just feel awful because I used to be very good at understanding algebra, in class with a teacher but learning it by myself again is very hard for me. Since multiplication is just a short cut to addition, I assume the rules are the same for multiplication Rules for adding odd and even numbers: If you add together two even numbers, the result is an even number If you add together two odd numbers, the result is an even number If you add together one even number and one odd number, the result is an odd number Here's what's confusing me: "Next, we developed our first result that we proved, rather than assumed. (a proved result is called a theorem.) We set out to prove the addition properties for odd and even numbers. We realized that any even number could be written in the form 2 x n, where n is some natural number. (I think a natural number times a natural number always equals a natural number. if you divide or subtract a natural number it doesn't) An odd number can be written in the form 2 x n + 1 We tried adding together one even number called 2 x n and another even number called 2 x m, calling the result sum s s = (2 x m) + (2 x n) Using the distributive property, s= 2 x ( m + n) From the closure property, m + n must be a natural number, so s can be written in the form s = 2 x (some natural number) Therefore, s must be even Next, we tried adding together two odd numbers, called 2 x m + 1 and 2 x n + 1 (again calling the result s) s= (2 x m + 1) + (2 x n + 1) s = 2 x m + 2 x n + 2 s = 2 x (m + n + 1) Since m + n + 1 must be a natural number, it follows that s must be even. We had one more combination to do: the sum of an odd number (which we called 2 x m +1 ) and an even number (which we called 2 x n): s = (2 x n ) + (2 x m + 1 ) s = 2 x (m + n) + 1 Since 2 x (m + n ) must be even, it follows that 2 x (m + n) + 1 must be odd. "We did it!" The professor exclaimed in amazement. "We can prove general behavior rules by using symbols to stand for letters! I wasn't even sure that could be done!" Can someone please try and explain this? I've always liked learning not only how to do things, but WHY you do them, and this explains it, yet I feel its very confusing for an introductury chapter on algebra.