Proving area with radians

I see now that your formula is correct, very clever. Sorry, I wasn't thinking clearly.In summary, a sector of a circle with perimeter 20cm, radius r, and angle θ radians has an area of Acm^2. It can be proven that A = 25-(r-5)^2 by using the formula A = 1/2r^2θ and the fact that the perimeter of the sector is 20cm. By solving for θ and substituting it into the formula, the proof can be easily completed.
  • #1
resresd
10
0
in a circle with perimeter of 20cm a sector has radius r, angle θ radians and area Acm^2
prove that A= 25-(r-5)^2

A=1/2 r^2 θ
c=2Πr

the only thing that I can think to do is c=2Πr therefore 20=2Πr
10=Πr r=10/Π
so then A=1/2 r^2 θ
=1/2 (10/Π)^2 θ
= θ (100/2Π^2)
 
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  • #2
Why don't you post the entire question again, and in a neat way, it will make life easier for everybody here, and surely you will get more responses!

EDIT: you can just edit the first post, and delete the others, or ask a PF to delete the others.
 
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  • #3
i can't seem to get the 2s to show up superscript...is there a particular way?
 
  • #4
you might want to use LATEX if you are familiar with that at all? or you can just do it
r^2, and we will know that r is raised to the power of 2.
 
  • #5
thanks, i hope this is better
 
  • #6
Honestly, it looks to me like that statement is not true and so cannot be proved. For one thing, it does not involve "[itex]\theta[/itex]" and that can't be right.
 
  • #7
I believe that the statement should have been like this:

A sector of a circle has a perimeter of 20cm and a area of "A" and the circle has a radius of "r". Prove that "A = 25-(r-5)(r-5)"

Now with simple methods, show that the arc of sector is (20-2r). Find the angle of sector in terms of "r". Then substitute the angle to the area of sector and it is proved easily.
 
  • #8
If you are not given the angle, how could you possibly prove that the length of the arc of the sector is 20- 2r? The length obviously depends on [itex]\theta[/itex].
 
  • #9
Indeed it does, but the perimeter also allows to find the Arc length, since the perimeter is the addition of the three sides (Arc length and two radii):

(Length of Arc) + (2 * radius) = Perimeter of Sector

or, Length of Arc = Perimeter of Sector - (2 * radius)

or, Length of Arc = 20 - 2r
 
  • #10
OH! The original post read "a circle with perimeter of 20cm" and when you changed it to "A sector of a circle has a perimeter of 20cm " I was still thinking about the circled and just thought about the length of the arc.
 

1. What is the concept of proving area with radians?

Proving area with radians is a method used in mathematics and physics to measure and calculate the area of a sector or portion of a circle by using radians as the unit of measurement instead of traditional units such as degrees.

2. How is the area of a sector calculated using radians?

The formula for calculating the area of a sector in radians is A = (1/2) * r^2 * θ, where r is the radius of the circle and θ is the central angle in radians. This formula is derived from the formula for calculating the area of a circle, A = π * r^2, where π is equal to 180 degrees or π radians.

3. What is the benefit of using radians instead of degrees in calculating area?

Radians are considered a more natural unit of measurement for angles and are especially useful in trigonometry and calculus. When used to calculate the area of a sector, radians provide a more precise measurement and make it easier to compare and analyze different sectors of a circle.

4. How are radians converted into degrees?

One radian is equal to about 57.3 degrees. To convert radians to degrees, multiply the value in radians by (180/π) or approximately 57.3. For example, 2 radians is equal to 2 * (180/π) = 114.6 degrees.

5. Can radians be used to measure the area of any shape?

No, radians are specifically used to measure the area of a sector or portion of a circle. They cannot be used to measure the area of other shapes such as triangles, squares, or rectangles.

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