The question I'm given is:(adsbygoogle = window.adsbygoogle || []).push({});

Newton's second law is given by [tex] \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}

\over F} = \frac{{d\vec p}}{{dt}}[/tex]. If the force is always parallel to the velocity, show that [tex] \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}

\over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}

\over a} [/tex].

Now, how do I get started on this thing?

Also, what I'm really wondering is how this is actually applied. When they say [tex] \mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}

\over F} = \gamma ^3 m\mathord{\buildrel{\lower3pt\hbox{$\scriptscriptstyle\rightharpoonup$}}

\over a} [/tex]… what gamma is being used? Also, are we looking at the change in momentum from wrt to the K frame?

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# Homework Help: Proving F=y^3ma in relativity

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