- #1

tuly

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cosh^2 X=(cosh (2X)+1)/2

sinh(X+Y)=sinh X.cosh Y+cosh X.sinh Y

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- Thread starter tuly
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- #1

tuly

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cosh^2 X=(cosh (2X)+1)/2

sinh(X+Y)=sinh X.cosh Y+cosh X.sinh Y

- #2

da_willem

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- #3

Curious3141

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- #4

amcavoy

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[tex]\cos{2x}=\cos^2{x}-\sin^2{x}=2\cos^2{x}-1[/tex]

From here, you can solve for [itex]\cos^2{x}[/itex] and you will have your answer for circular functions. Now, apply this to hyperbolic functions.

- #5

tuly

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thanks for your help...

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