(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Prove that [itex]\varphi[/itex](n)→∞ as n→∞. n[itex]\in[/itex]Z

2. Relevant equations

[itex]\varphi[/itex](n) = the number of integers less than n that are coprime to n.

3. The attempt at a solution

My professor said that we need to show that [itex]\varphi[/itex](n) is always greater than some increasing estimate of itself. I'm really not sure how to even go about applying this. Any help you could offer would be really appreciated.

What I was thinking of doing would be to say let k be the integer with the maximum value of the totient function. k=p_{1}^{[itex]\alpha[/itex]1}...p_{n}^{[itex]\alpha[/itex]n}where p_{i}is a prime number. So [itex]\varphi[/itex](k) = [itex]\varphi[/itex](p_{1}^{[itex]\alpha[/itex]1}...p_{n}^{[itex]\alpha[/itex]n})=[itex]\varphi[/itex](p_{1}^{[itex]\alpha[/itex]1})...[itex]\varphi[/itex](p_{n}^{[itex]\alpha[/itex]n}). Multiply k by any prime greater than p_{n}, called p_{l}. Call this number j. Then [itex]\varphi[/itex](j)=[itex]\varphi[/itex](p_{1}^{[itex]\alpha[/itex]1})...[itex]\varphi[/itex](p_{n}^{[itex]\alpha[/itex]n})[itex]\varphi[/itex](p_{l}^{[itex]\alpha[/itex]l}). This new multiple is greater than zero (I would write out the basis case in order to guarantee this), so the second equation is greater than the first, so there cannot be an integer with the maximum value of the totient. In other words, as n increases, the totient function increases.

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# Proving that the totient function increases infinitely

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