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Proving that torque is m X B

  1. Nov 7, 2016 #1
    1. The problem statement, all variables and given/known data
    Starting from the Lorentz force law, in the form of Fmag = ∫ I (d× B), show that the torque on any steady current distribution (not just a square loop) in a uniform field B is m × B.

    2. Relevant equations
    I looked at the solution I found in this thread here, but I don't understand the step after you take the derivative of both sides of the torque equation. Why would you use that method in the next step, and how? Where did it come from?

    I have Griffiths 4ed.

    3. The attempt at a solution
    This is all I know how to do.
    ubsqgCZ.jpg
     
  2. jcsd
  3. Nov 7, 2016 #2

    I like Serena

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    Hi mister ghoul! :oldsmile:

    What is ##\mathbf m##?
     
    Last edited: Nov 8, 2016
  4. Nov 8, 2016 #3
    Hi,
    I belive that m is magnetic dipole moment. m = Ia
     
  5. Nov 8, 2016 #4

    I like Serena

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    Okay... so what is ##\mathbf a##?
    We'll need some expression to substitute, which will hopefully lead to the requested result.
     
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