- #1
grimster
- 39
- 0
J=sum from i=1->n of <X_i^q - X_i>
V={polynomials f with deg in X_i < q)
k is a field with q elements. k[X] is the polynomial ring in "n" variables".
i am supposed to prove that V+J=k[x].
i was told that this could be done with induction for the number "k", by using the following notion.given a polynomial f E k[x]:
k0=the sum of L_j. j=1..."number of monomials".
L_j is the sum of of the "degrees" of the "indeterminates/variables" which are >q in monomial "j".
so L_j=sum of all s_i, where s_i > q. s_i are the exponents of the monomial which are >q.
so somehow i have to show that this is true for <k0 and then it is true for k0. or something like that?
does anyone know what I'm saying here? it might be a little confusing. just ask if there's anything you don't understand.
V={polynomials f with deg in X_i < q)
k is a field with q elements. k[X] is the polynomial ring in "n" variables".
i am supposed to prove that V+J=k[x].
i was told that this could be done with induction for the number "k", by using the following notion.given a polynomial f E k[x]:
k0=the sum of L_j. j=1..."number of monomials".
L_j is the sum of of the "degrees" of the "indeterminates/variables" which are >q in monomial "j".
so L_j=sum of all s_i, where s_i > q. s_i are the exponents of the monomial which are >q.
so somehow i have to show that this is true for <k0 and then it is true for k0. or something like that?
does anyone know what I'm saying here? it might be a little confusing. just ask if there's anything you don't understand.