- #1

- 5

- 0

Dt[R(t) X R'(t)] = R(t) X R"(t)

Any suggestions?!

- Thread starter multivariable
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- #1

- 5

- 0

Dt[R(t) X R'(t)] = R(t) X R"(t)

Any suggestions?!

- #2

lurflurf

Homework Helper

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[R(t) X R'(t)]' = R'(t) X R'(t)+R(t) X R"(t)

for any sensible derivative

thus

[R(t) X R'(t)]' = R(t) X R"(t)

if and only if

R'(t) X R'(t)=0

clearly true for cross product

- #3

HallsofIvy

Science Advisor

Homework Helper

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Is the "Dt" derivative with respect to t? i.e.(R x R')' ?

Dt[R(t) X R'(t)] = R(t) X R"(t)

Any suggestions?!

## Homework Statement

## Homework Equations

## The Attempt at a Solution

What have you

Do you know that the "product rule" from Calculus I is still true for vector products? What does that give you?

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