# Pseudo Real Group if anomaly free

1. Oct 25, 2005

### robousy

I am working a problem from the Mohapatra textbook unification and supersymmetry and the question is to show that if any rep of a grp is pseudo real then it is automatically anomaly free.

All I know is that for a pseudo real group G = G* (the conjugate is the same as the original group). The group is not real though. :yuck:

I've been searching the web and books for a couple of hours now to no avail so thought I'd leave the question here.

2. Oct 25, 2005

Staff Emeritus
May I suggest you post this question on the sci.physics.strings board, which you can access through the Strings Branes and LQG subforum. That board is visited by expert string theorists who are likely to have an answer for your question; they are very interested in anomaly cancelation. But they are not likely to visit this Particle Physics subforum.

3. Oct 25, 2005

### robousy

ok, thanks!

4. Oct 28, 2005

### Haelfix

Mmm, this is a bit of a technical question, you'll want to double check me (say with Weinberg vol 2).

But you basically listed the reason *why*, namely when the left handed fermion fields furnish reps that are equivalent to the complex conjugate rep. Eg the representation of the gauge algebra (take its complex conjugate) is related by a similarity transformation to itself

To see this, remember when you calculate the anomaly from the three point function, you can seperate it into symmetric and antisymmetric parts by group index. The anomaly is wholely contained in the symmetric part of this, so you have to do a little bit of algebra (subbing in the similarity condition of the representation into the symmetric part) and you will come out with the required reality or pseudo reality to be anomaly free.

Note that some standard model groups will contain this gauge anomaly, so there you will have to look for cancellations to occur, or else you have an inconsistent theory. Its one of the miracles of SU(3)*SU(2)*U(1) that the required cancellations *do* occur (a deeper reason maybe is that this group is an rep of SO(10) which is by the above anomaly free)

Last edited: Oct 29, 2005
5. Oct 30, 2005

### robousy

Hey Haelfix. Thanks for your response. I'm still getting used to calculating the anomaly. I've done is so far using young tableux and I've also seen an equation in Mohapatras book that is related to the trace of generators.
Could you possibly give me a reference to the equation you are tallking about - ie regarding the 3 pt function. I have most QFT books - perhaps Weinberg vol 2?

Thanks again.