PSI Calculations

  • Thread starter daviddjh
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Suppose you have a hollow cube with a volume of 504c3. The inside of the cube has a psi of 94 and is just air. Now suppose that a hole opened in the bottom of this cube with an area of 12.56cm2 that leads to a hollow cylinder that is 14 cm long with a radius of 2cm. Now how would you go about calculating the psi of this whole structure after the hole is opened, the air is released and the volume has changed.
 

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  • #2
Nugatory
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Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
 
  • #3
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Does the cylinder contain air at normal atmospheric pressure, or is it vacuum?
The cylinder would have a vacuum inside it
 
  • #4
Nugatory
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The cylinder would have a vacuum inside it
OK - that makes it easy. Boyle's Law, ##PV=c## where ##c## is a constant, will get you an answer in short order.

(Boyle's Law would still get you there if the cylinder weren't a vacuum, but it would be more work).
 

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