Calculating Final Speeds of Colliding Pucks on an Air-Hockey Table

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In summary: Thanks for your help and patience.In summary, the conversation was about a collision between two pucks on an air-hockey table. The drawing provided showed the collision, with Puck A having a mass of 0.028 kg and moving along the x-axis with a velocity of +5.5 m/s, while Puck B had a mass of 0.068 kg and was initially at rest. The question was to find the final speed of both pucks after the collision, assuming it was elastic. The conversation also touched upon the use of momentum formulas and trigonometry to solve the problem. The conversation ended with the poster realizing their mistake and solving the problem.
  • #1
davidphysics
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Hey. This is my first post... here's my question [Diagram Attached]:

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.028 kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.068 kg and is initially at rest. After the collision, the two pucks fly apart with the angles shown in the drawing.

Find the final speed of
(a) puck A and

(b) puck B. [both in m/s]

I am having trouble with this and although I know to use conservation of momentum, should I assume its elastic?

If you could post an explanation that would be great, but I would also like a final answer in numbers please.
 

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  • #2
davidphysics said:
If you could post an explanation that would be great, but I would also like a final answer in numbers please.

No one is interested in doing your homework for you, but rather in helping you understand. So don't be too disappointed with only an explanation.

Have you tried using momentum formulas and a little trig? Put in a little effort so people can see where you're having trouble.
 
  • #3
tony873004 said:
No one is interested in doing your homework for you, but rather in helping you understand. So don't be too disappointed with only an explanation.

Have you tried using momentum formulas and a little trig? Put in a little effort so people can see where you're having trouble.

Ok sorry let me explain what I've gotten to... Basically I've set up both horizontal and vertical equations for both Po=Pf and Ko=Kf. Before I go any further, am I correct to assume that it is elastic and that the kinetic energy is conserved?

To be honest I don't wan't to use up my 4 trys on webassign, which I'm sure your familiar with.

By the way, thanks for the quick response.
 
  • #4
And when I plug in the values for "v" in those formulas I should use for example Vacos65 and Vasin65 for the horiz and vert respectively, right?

For some reason I keep getting the Vert for a and b=0, because both the initial momentum and kin energy=0. So when I solve I get Vert: Va=Vb=0... I feel like I'm doing something very stupid.
 
  • #5
Yes, I'm familiar with the 4 attempts :)

Unless energy is being carried away in sound waves or by other means, I would guess your assumption is correct. Your picture isn't approved yet, so I can't be sure.
 
  • #6
tony873004 said:
Your picture isn't approved yet, so I can't be sure.

O didn't realize that, please read my post that I just posted a second ago, and I'll put the image on imageshack.

POSTED:http://img135.imageshack.us/img135/9303/0732jj6.gif

And when I plug in the values for "v" in those formulas I should use for example Vacos65 and Vasin65 for the horiz and vert respectively, right?

For some reason I keep getting the Vert for a and b=0, because both the initial momentum and kin energy=0. So when I solve I get Vert: Va=Vb=0... I feel like I'm doing something very stupid.
 
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  • #7
Bump (sorry)
 
  • #8
Keep in mind your total momentum before the collision was completely on the x-axis. There was no momentum on the y-axis. So afterwards, the y-components of the momentums of your two objects should also equal zero since it is conserved.

I'm on my way out the door, so I can't help you further. But others are sure to jump in. Good luck, and welcome to the forum.
 
  • #9
tony873004 said:
Keep in mind your total momentum before the collision was completely on the x-axis. There was no momentum on the y-axis. So afterwards, the y-components of the momentums of your two objects should also equal zero since it is conserved.

I'm on my way out the door, so I can't help you further. But others are sure to jump in. Good luck, and welcome to the forum.

Wow, then that image is very deceiving... thanks for your help -Everyone else JUMP IN! :)

Just thinking of it that makes perfect sense, now I see how these pictures mess with your mind.

Disregard everything above, yea so the Vert momentum up = vert momentum down
 
  • #10
For some reason I keep getting the Vert for a and b=0, because both the initial momentum and kin energy=0. So when I solve I get Vert: Va=Vb=0...
But the initial momentum is not zero. It is in the vertical direction, but not in the horizontal. The initial kinetic energy is not zero either, since A is moving.
 
  • #11
hage567 said:
But the initial momentum is not zero. It is in the vertical direction, but not in the horizontal. The initial kinetic energy is not zero either, since A is moving.

I mean the initial VERT momentum. But thanks for "The initial kinetic energy is not zero either, since A is moving." Can't believe I screwed that up. I don't have any more time now, but I'll work on that tomorrow and will come back to this forum later.

Thanks! and cya
 
  • #12
You need to apply conservation of momentum and energy. Initial conditions do not require you to resolve the velocity vector into components. You need to resolve the velocity vector into x and y components for the final condition.
 
  • #13
Hi. I am still having trouble and would like help. Its not working out.

Thanks
 
  • #14
Show how you set up your equations. We can't find what you're doing wrong if you don't show us your work.
 
  • #15
Nevermind - I figured it out. I was making it much too difficult. All I had to do was Po=Pf for the horiz and vert, and solve that set of equations.
 

What is the Puck Collision Problem?

The Puck Collision Problem is a scenario in which two or more pucks, or small discs, collide with each other on a frictionless surface. It is often used as a thought experiment in physics to demonstrate principles of momentum and energy conservation.

How is the collision of the pucks modeled?

The collision of the pucks is typically modeled using the laws of conservation of momentum and energy. This involves calculating the initial and final velocities of each puck and using equations to determine the resulting velocities after the collision.

What factors affect the outcome of the Puck Collision Problem?

The outcome of the Puck Collision Problem can be affected by various factors such as the initial velocities and masses of the pucks, the angle at which they collide, and the elasticity or "bounciness" of the surface they are colliding on.

What can be learned from studying the Puck Collision Problem?

Studying the Puck Collision Problem can help us understand the principles of momentum and energy conservation, as well as how these laws apply to real-world scenarios. It can also help us develop mathematical and computational skills for solving complex problems.

How is the Puck Collision Problem relevant to real life?

The Puck Collision Problem has many real-life applications, such as in the study of collisions between particles in physics and collisions between vehicles in traffic accidents. It can also be used in the design and testing of sports equipment, such as hockey pucks or billiard balls.

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