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Puck collision with rod using angular momentum conservation
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[QUOTE="ChiralSuperfields, post: 6850428, member: 731016"] Thank you for your reply [USER=192687]@kuruman[/USER] ! Sorry I did not realize I mixed up the order! Taking the angular momentum of the puck about the z-axis, ## \vec L = m\vec r \times \vec v ## ## \vec L = m(x\hat i + y\hat j) \times (v_x\hat i + v_y\hat j) ## ## \vec L = mxv_y \hat k - myv_x \hat k ## Therefore the angular momentum of the system is ##\vec L= -mRgt \hat j + mxv_y \hat k - myv_x \hat k## Many thanks! [/QUOTE]
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Puck collision with rod using angular momentum conservation
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