http://i.imgur.com/TbYIHnb.png?1(adsbygoogle = window.adsbygoogle || []).push({});

So, if I have a pull up and apply a current source. How would I need to read/calculate resistance?

V=IR

I = 5V/8k = .0006A would result in a voltage drop of close to 5V

Using a current source/Voltage reader I supply .0006A which should equate to ~5V drop

But when I read my voltage reader I get 9.83V. Is this correct?

Then my resistance would be 9.83/.0006 ~ 16.4k ?

These calculations do not seem correct.

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# Pull up resistor calculation

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