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Pulley and 2nd newton law

  1. Nov 22, 2009 #1
    1. The problem statement, all variables and given/known data

    http://img69.imageshack.us/img69/2429/phyq1.jpg [Broken]

    2. Relevant equations
    to find the acceleration of the 2 objects and the Tension Force.


    3. The attempt at a solution

    since only 1 pulley used, a=a1=a2, then
    m1a=T (1)
    m2a=-T+m2gsin45 (2)

    i wonder what happen to the m2gcos 45?? and is the 2 equations right for my assumption? thanks
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Nov 22, 2009 #2

    ideasrule

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    m2gcos45 is the normal force applied by m2, which isn't really important unless friction is considered (or unless it's so big that something breaks).
     
  4. Nov 22, 2009 #3
    but is the 2 equations right? because i am still ponder over m2a=-T+m2gsin45 or m2a=T+m2gsin45 ?? really sad my basic wasnt good...
     
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