1. The problem statement, all variables and given/known data Two masses 53gms and 45gms are connected by a light inextensible string passing over a smooth pulley and hung freely. Find a) the velocity after 3 seconds b) distance traversed in 3 seconds c) distance traversed in the third second d)if the string is cut after 3 seconds how much farther will the masses move in the next one second 2. Relevant equations common acceleration, a= (m1-m2)g/m1+m2 S=ut+1at^2/2, v=u+at, v^2=u^2+2as 3. The attempt at a solution I solved a, b and c but what I am finding difficult to solve is part d. The common acceleration gained after 3 seconds is 0.8m/s^2 and the velocity is 2.4m/s and the distance traversed in that time is 3.6m. When the string is in the normal state the end which is tied to the lighter mass will move up by 3.6m and the end tied to the heavier mass will go down by 3.6m. When the string is cut the initial velocity becomes 2.4 and final velocity becomes 0. The height through which the lighter mass moves is 0.298m. But the answer is 2.5m Tell me where i am going wrong..