(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two blocks are connected over a pulley. The mass of block A is 10 kg and the coefficient of kinetic friction between A and the incline 0.20. Angle [tex]theta[/tex] of the incline is 30 degrees. Block A slides down the incline at constant speed. What is the mass of block B?

2. Relevant equations

Fs=mgsin[tex]theta[/tex]

Sin[tex]theta[/tex]= Fs/mg

3. The attempt at a solution

I tried using substition in order to find the second mass, but that route bore no fruit.

9.8 x 10 x sin 30= 49

Fs=49

T- mgsin[tex]theta[/tex]=ma

T-49=ma

T=ma+49

-T+m(subscript 2)g= M(subscript2)a (we substitute t for ma+49)

-(m(subscript 1)a+49)+m(subscript 2)g= M(subscript 2)a

-msub1-49+msub2g=msub2a

all that boils down to is

(9.8m(sub2)-49)/(10+msub2)= a

How exactly am I supposed to find the second mass without knowing the acceleration?

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# Homework Help: Pulley Block Mass Problem

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