1. The problem statement, all variables and given/known data Two blocks are connected over a pulley. The mass of block A is 10 kg and the coefficient of kinetic friction between A and the incline 0.20. Angle [tex]theta[/tex] of the incline is 30 degrees. Block A slides down the incline at constant speed. What is the mass of block B? 2. Relevant equations Fs=mgsin[tex]theta[/tex] Sin[tex]theta[/tex]= Fs/mg 3. The attempt at a solution I tried using substition in order to find the second mass, but that route bore no fruit. 9.8 x 10 x sin 30= 49 Fs=49 T- mgsin[tex]theta[/tex]=ma T-49=ma T=ma+49 -T+m(subscript 2)g= M(subscript2)a (we substitute t for ma+49) -(m(subscript 1)a+49)+m(subscript 2)g= M(subscript 2)a -msub1-49+msub2g=msub2a all that boils down to is (9.8m(sub2)-49)/(10+msub2)= a How exactly am I supposed to find the second mass without knowing the acceleration?