1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Pulley on a table

  1. Jun 9, 2008 #1
    1. The problem statement, all variables and given/known data

    Mass A, 15 kg, is on a table, connected by a massless rope and frictionless pulley, to mass B, 8 kg, which is hanging off the side of the table. The kinetic friction coefficient is 0.14. Find the acceleration of the blocks.

    3. The attempt at a solution

    I've followed the problem all the way through, and I understand the gist of it, but I'm stuck on one tiny conceptual issue. Combining equations since the acceleration of block A equals that of block B, gives you a = (massB)(g) - (friction)(massA)(g) / (massA + massB). My question is that when trying to solve it on my own, I isolated block A. The forces on block A are the force of gravity, the normal force, the tension from the rope, and the force of friction. Since block A is not moving vertically, I look at only the tension and the friction. The tension is only due to the weight of block B, so that's (massB)(g). The opposing force of friction is (friction coeff)(massA)(g). So, in my mind, the net force on block A is F = (massA)(a) = (massB)(g) - (friction coeff)(massA)(g). Basically the same thing as the correct equation above, except I only divide by the massA, not (massA + massB). If I'm only looking at block A, why do I need to include the mass of block B?? Pls help!!
  2. jcsd
  3. Jun 9, 2008 #2

    Doc Al

    User Avatar

    Staff: Mentor

    This is an error: The tension does not simply equal the weight of block B. (If it did, the net force on Block B would be zero.)
    Since you don't know the tension (you'll have to solve for it), the best you can do is to call it "T" and write: F = (massA)(a) = T - (friction coeff)(massA)(g).

    You'll need a second equation to combine with this to solve for the acceleration and the tension. Get that second equation by isolating Block B and writing a similar force equation.

    (When you combine those two equations you'll get the equation you began with.)
  4. Jun 9, 2008 #3
    Oh my goodness, THANK YOU SO MUCH! You have no idea how much this was hurting my brain! =P
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Pulley on a table