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Pulley problem! Help! !

  1. Oct 31, 2012 #1
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution

    There are two bodies of mass 5kg and 1 kg on either sides of a pulley. (The string stays vertical and straight at all times). The heavier mass is doubled. The downward acceleration on the string of the hevier mass is "x". Find "x" when g=10m/s-2.
    Please help fast!!!!!!!!
    Desperate!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 31, 2012 #2

    tiny-tim

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    welcome to pf!

    hi jk13! welcome to pf! :smile:

    (try using the X2 button just above the Reply box :wink:)
    (what do you mean by "The heavier mass is doubled" ? :confused:)

    call the tension "T", and do F = ma twice, once for each mass …

    show us what you get :smile:
     
  4. Nov 1, 2012 #3
    Re: welcome to pf!

    The mass 5 kg is doubled. :p
    f=ma
    f=5*10=50
    f=1*10=10
    Correct?
     
  5. Nov 1, 2012 #4
    Re: welcome to pf!

    Help me please?! :(
     
  6. Nov 1, 2012 #5

    tiny-tim

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    hi jk13! :smile:
    no, that's weight = mg

    you need Ftotal = ma, and you need to include the tension, T, and the acceleration, a
     
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