- #1

- 2

- 0

O |

| |

| |

| |

C

D

| |

| |

B |

Anyways, the problem wants to determine the acceleration of A and the distance A travels before stopping, and mass of the pulleys and cables can be neglected.

So for A, it should be [tex]\sum[/tex]Fx = 100 * sin(36.9) - N * 0.2 - T = massA*accelA

where N is just the normal force: 100*cos(36.9)

And I think the force's on B would be [tex]\sum[/tex]Fy = 50 - T = massB*accelB

Now, that leaves the lengths of cord, which should give two equations as it's two separate cords. I believe the length of the cord directly attached to A will be Sa + 2Sc = L1

But I'm unsure of the second cord so here's where I'm stuck. Also I'm not entirely sure everything else I've done is right either so if someone wouldn't mind checking that would be great.