Problem: The system shown consisting of a 20-kg collar A & a10-kg weight B is @ rest, when a constant 500-N force is applied to collar A (a) Determine the Velocity of A just before it hits the ground @ C (b) solve part a replacing the weight B w/a 98.1-NA downward force. Neglect friction and the mass of the pulleys. (a) Can I start by figuring the weight of A vs. the counter weight. then sumF=ma on the collar then use a constant Accel. Eq. to find Vel. Or do I use some sort of Kinetic Energy Eq's. (I hate these) ?? (sum)F=ma 500-N=200-kg*a a=25m/s^2 V^2=Vo^2+2aX V^2=0+2(25m/s^2).6m V=5.43m/s Is this right or is there more forces acting on A. (I assumed this because A starts at rest.) (b) what would be the difference in solving this one? Any Help Would Be Appreciated.