Pulleys and friction

  • #1
Alright, I know I have this stuff somewhere at school, but unfortunately, I can't leave it till tom.

A mass is at rest on a horizontal plane, and is attached by a second mass that is threaded through a pulley and is suspended in the air. What is the coefficient of friction?

The formula I've been using is

M(1)a(coefficient of friction) = M(2) (g-a)
(sorry about the horrible representation)

rearranged into this:

M(2) (g-a) = (coefficient of friction)
M(1)a

where a= acceleration
M= mass
g = gravity = 9.81

Unfortunately, upon plugging in my numbers from the experiment, I keep getting 7.5171...for the coefficient of gravity...which to me seems impossibly high!
 

Answers and Replies

  • #2
The system is at rest, so what's acceleration supposed to be?

cookiemonster
 
  • #3
Oops, forgot to mention that the system BEGINS at rest and then the suspended mass is released, hence the acceleration...wow, I feel dumber already! :uhh:

Acceleration was 0.6525 m/s(squared)
 

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