1. The problem statement, all variables and given/known data A sled of mass 480kg is pulled along the ice at a constant speed by means of a rope inclined upward at 25° to the horizontal. If the force of tension in the rope is 350N, what is the coefficient of friction between the sled and the ice? 2. Relevant equations 3. The attempt at a solution Since the system is at equilibrium, Ffr = Fa * cos25° = 350N *cos25° = 317.2N FN = 480kg * 9.8m/s2 = 4704N μK= Ffr/Fn = 317.2N/4704N =0.067 Anyone mind taking a look at this to see if I approached this wrong?