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Pully descending

  1. Nov 16, 2004 #1
    There is a pully with a rope though it. The rope of the left side is on the ground connected to a massless bucket. The right side has a man on a cliff about to jump on the rope. The man wants to descend 9.144m in exactly 4s. The question asks how much weight to put into the massless bucket for the man to descend 9.144m in exactly 4s. There isn't any inital velocity.

    So, I need to find the acceleration of the man:
    d=.5at^2
    9.144m=.5(a)4^s
    a=1.143m/s^2

    Now I will find how much the mass of the bucket has to be:
    m1a1=m2a2
    m1(9.81)=(81.65kg)(9.81-1.143)
    m=72.14kg

    is this correct?
     
  2. jcsd
  3. Nov 16, 2004 #2
    Im taking it that the problem said the man weights 81.65kg, right?
     
  4. Nov 16, 2004 #3
    yes, forgot to say that
     
  5. Nov 16, 2004 #4
    Seems correct 2 me, good job. :smile:
     
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