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A wire 5.0 m long and having a mass of 130 g is stretched under a tension of 220 N. If two pulses, separated in time by 30.0 ms, are generated, one at each end of the wire, where will the pulses first meet?

m (distance from the left end of the wire)

From my deduction the each wave starts from the opposite side.

I figured out the v=91.9866 b/c the square root of 220/(.13/5)=91.9866 m/s

I then set up equations

t=time x=distance

91.9866t=x

91.9866(t-3*10^-3)=5-x

I got x to equal 2.6379799 m

However, I am not certain if this is the correct answer and I am down to my last submission. I was wondering if anyone could agree with what I got.