A thin spherical shell lying on a rough horizontal floor is hit by a cue in such a way that the line of action of force passes through the centre of the shell.as a result the shell starts moving with a linear speed v without any initial angular velocity.find the linear speed of the shell after it starts purely rolling.
The Attempt at a Solution
i would use the principle of conservation of energy here as angular momentum is not conserved here because there is an external torque acting on it by friction.
1/2mv2=1/2mv'2+1/2Iω2 (v' is the linear velocity of the cue after it starts purely rolling)
But the answer happens to be v'=3v/5