(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A thin spherical shell lying on a rough horizontal floor is hit by a cue in such a way that the line of action of force passes through the centre of the shell.as a result the shell starts moving with a linear speed v without any initial angular velocity.find the linear speed of the shell after it starts purely rolling.

2. Relevant equations

1/2mv^{2}=1/2mv'^{2}+1/2Iω^{2}

3. The attempt at a solution

i would use the principle of conservation of energy here as angular momentum is not conserved here because there is an external torque acting on it by friction.

1/2mv^{2}=1/2mv'^{2}+1/2Iω^{2}(v' is the linear velocity of the cue after it starts purely rolling)

v^{2}=(3/2)v'^{2}(I=1/2mr2^{2})

But the answer happens to be v'=3v/5

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Pure rolling

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