I noticed that the temperature coefficient of resistivity of pure silicon is a rather high negative number, so just out of curiosity I wanted to see at what temp the resistivity would drop to zero. The formula is ρ-ρ0 = ρ0α(T-T0) where ρ is the final resistivity, ρ0 is the reference resistivity, α is the temperature coefficient of resistivity, T is the final temp and T0 is the reference temp My book gives the α at a reference temp of 293 K. At this temp, ρ0 is 2.5*10^3 and α is -70*10^-3. Therefore, if we set the final resistivity (ρ) to 0: -ρ0 = ρ0α(T-T0) -1/α = T-T0 T = -1/α + T0 = -1/(-70*10^-3) + 293 = 307 K I have been told that this can't possibly be right, but no one will tell me exactly why. I have been told that what I'm doing wrong is "assuming that resistivity does not change with temp", even though I obviously am taking that into consideration, since I am using an equation that says approximately how resistivity changes with temp. I have also been told that the linear approximation equation I am using holds only for a limited range with respect to the reference temp, and I also know that it won't hold for huge temps, but 307 K is not too far from room temp. (and actually, according to my book, this equation holds "over a rather large temperature range") Could someone please point out exactly what I am doing wrong? There must be something wrong because I dont think silicon is a conductor at some 35-ish degrees Celsius..