1. The problem statement, all variables and given/known data A 5.00-kg box sits at rest at the bottom of a ramp that is 8.00m long and that is inclined at 30.0° above the horizontal. The coefficient of kinetic friction is μk = 0.40, and the coefficient of static friction is μs = 0.50. What constant force F, applied parallel to the surface of the ramp, is required to push the box to the top of the ramp in a time of 4.00s? g = 9.8 in my class 2. Relevant equations Fg = m(g) FN = m(g)(cos(θ)) Ffk = μk(FN) FNET = m(a) 3. The attempt at a solution Fg = 5(9.8) = 49N FN = 5(9.8)(cos(30)) = 42.44N Ffk = .40(42.44) = 16.98N This is where I get stuck. I am able to find the minimum amount required to get it to start and keep moving but not what the question is asking. My textbook does not explain this topic very well so I was getting frustrated.