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Push pull stage current gain?

  1. Mar 22, 2010 #1
    I'm trying to figure out the currubt gain for a class ab push pull amp. I know that it's basically two emitter followers, so am I correct in assuming that the current gain is just Beta?
  2. jcsd
  3. Mar 22, 2010 #2
    the current gain is basically the emitter current over the base curent

    [tex]\frac{{{i_e}}}{{{i_b}}}\quad = \quad {h_{fe}} + 1[/tex]

    With darlingtons you can forget the 1, but it can be significant with single transistors at high currents where the gain is maybe not more than 10.
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