1. Mar 22, 2010 #1

   saad87

   

   I'm trying to figure out the currubt gain for a class ab push pull amp. I know that it's basically two emitter followers, so am I correct in assuming that the current gain is just Beta?

    

   saad87, Mar 22, 2010
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3. Mar 22, 2010 #2

   Studiot

   

   the current gain is basically the emitter current over the base curent
   
   [tex]\frac{{{i_e}}}{{{i_b}}}\quad = \quad {h_{fe}} + 1[/tex]
   
   With darlingtons you can forget the 1, but it can be significant with single transistors at high currents where the gain is maybe not more than 10.

    

   Studiot, Mar 22, 2010

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