A force is applied to an initially stationary block of mass 2.65 kg that sits on a horizontal floor as shown. The 81.0 N force is applied at θ = 50° angle to the vertical. The coefficients of friction between the floor and the block are μs = 0.895 and μk = 0.665. What is the acceleration of the block?
Newton's second law and trig
The Attempt at a Solution
First I broke the force into components, Fx=81sin50, Fy=81cos50. There are also the force of gravity, normal force, and friction acting on the block. So for sum of forces equations i have
Where did I go wrong????