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## Homework Statement

A stockroom worker pushes a box with mass 11.1 kg on a horizontal surface with a constant speed of 3.80 m/s. The coefficient of kinetic friction between the box and the surface is 0.170.

## Homework Equations

F=ma

w=mg

What horizontal force must be applied by the worker to maintain the motion?

I found that the Fapplied is 18.5N

If the force calculated in part A is removed, how far does the box slide before coming to rest?

This question I'm having problems on. Here is what I did

18.5N = 11.1kga

a=1.66666667 m/s^2

Then I used the equation of

Vfinal^2=Vinitial^2+2a[tex]\Delta[/tex]x

[tex]\Delta[/tex]x = 0 - 14.44m/s

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2(1.66666667)

[tex]\Delta[/tex]x=4.3m ?