You calculated the time to fall correctly. But you are using the wrong horizontal distance to calculate the horizontal speed of the box as it falls:Originally posted by paigegail
Consider horizontal
¥Äx = 7.5 + 5= 12.5 m
Relax....Originally posted by paigegail
Ok...so I have that. But what is SOOOOO EXTREMELY FRUSTRATING...IS WHAT DO I DO AFTER I HAVE ALL THAT!! The acceleration becomes 0.4163 m/s-squared-. F= ma.... that makes is 10.8(0.4163)=4.49604 N that's no where near the answer.
How did you calculate the acceleration?Originally posted by paigegail
K...I found acceleration wrong. I realized that.
Acceleration = 1.733 m/s -squared-
That's not what I got for acceleration. I got 2.13 m/s^{2}.Originally posted by paigegail
Acceleration = 1.733 m/s -squared-
You have a typo: the value for v is not 4.16, it's 4.61.Originally posted by paigegail
v-squared- = vo-squared- + 2aDelta X
4.163 -squared- = 0 + 2(5)a
17.330569 =10a
a=1.733