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Puzzling Equation

  1. Jan 28, 2010 #1
    I am reading an article that shows this equation

    (eqn 1) f(x) = f(x1)*f(x-x1) / [ (cot(x1) + cot(x-x1) ]

    an it continue that the solution to it is

    (eqn 2) f(x) = 1 / (sin(x) ).

    I admit that it is indeed easy to show that eqn 2 does fit to eqn 1 but I don't really have idea how to get eqn 2 out of eqn 1. Will anybody share their idea how to do this stuff? This puzzles me because it seems easy but I just dont know how to start it.
  2. jcsd
  3. Jan 28, 2010 #2
    Can you check and make sure you wrote this down correctly.

    Also, I assume x1 means [itex]x_1[/itex].

    Also, [itex]x_1[/itex] can be anything I want?

    Every detail to a question is important. There is no such thing as text talk in mathematics. ;)
    Last edited by a moderator: Jan 29, 2010
  4. Jan 28, 2010 #3
    Im sorry for the incomplete information.

    0< x_1 < x is the additional restriction.
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