What is the path on the pV diagram for an isobaric expansion from 2 m^3 to 5 m^3?

[ApexStudent1]

Draw the path in the pV diagram for an isobaric expansion from a volume of 2 m^3 to 5 m^3.



Idk which of these equations are needed because they all are given with this section...
ΔU=Q-W
ΔU=Q+W
W=PΔV
ΔU=Q
W=nRTln(Vf/Vi)
Q-W
ΔU=-W
ΔU=+W
e=W/Qh=1-Qc/Qh
e=1-Tc/Th
ΔS=Q/T




My attempt...

Graph with x being Volume and y being Pressure, a horizontal line from 2-5

 

[Thaakisfox]

An isobaric expansion means that the pressure is kept constant during the expansion. This means that when you graph the expansion on the pV diagram, you will have a line parallel to the V axis.
So what you did was right...

 

[thomate1]

m^3 would represent an isobaric expansion. This means that the pressure remains constant at a certain value while the volume increases. Therefore, the path on the pV diagram for an isobaric expansion from 2 m^3 to 5 m^3 would be a straight horizontal line at the pressure value. This is represented by the equation W=PΔV, where W is the work done, P is the constant pressure, and ΔV is the change in volume. This equation shows that the work done during an isobaric expansion is directly proportional to the change in volume. The path on the pV diagram would look like a rectangle, with the base representing the initial and final volumes (2 m^3 and 5 m^3) and the height representing the constant pressure.