1. The problem statement, all variables and given/known data If 1.15 moles of an ideal gas has a pressure of 3.60 atm, and a volume of 81.37 L, what is the temperature of the sample in degrees Celsius? 2. Relevant equations PV=nRT p = pressure v = volume n = number of moles r = 0.08206 L atm/(mol K) T = ? 3. The attempt at a solution So I did the problem by : 3.60 (81.37) = (1.15)(0.08206)(T) I found T to be 20.9 degrees K. I converted the temperature from K to C by doing K = C + 273 so 20.9 = C + 273. So the temperate in C is -252 degrees. However, I am still getting this wrong in the online homework. Can anyone help me figure out mistake?